Problem: A column 'Names' contains following values:
'Nitin'
'Ashok'
'Sanjeev'
Write a SQL to break these values into individual characters.
Solution:
select names,
substr(names,level,1) ch
from
(
select 'Nitin' names from dual
union all
select 'Ashok' names from dual
union all
select 'Sanjeev' names from dual
)
connect by prior names=names
and level<=length(names)
AND prior DBMS_RANDOM.STRING ('p',10) IS NOT NULL
TIME_BUCKET group by time period
-
We all know how to sum up by year select
to_char(trunc(hiredate,'Y'),'YYYY') year, count(*) from scott.emp group by
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1 week ago
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