Problem: Write an SQL query to convert a binary number to its Decimal equivalent.
Solution:
select sum(substr(&binary_number,rownum,1)*power(2,length(&binary_number)-rownum)) decimal_number from all_objects
where rownum<=length(&binary_number)
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TIME_BUCKET group by time period
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We all know how to sum up by year select
to_char(trunc(hiredate,'Y'),'YYYY') year, count(*) from scott.emp group by
trunc(hiredate,'Y') order by trunc(hire...
1 week ago
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